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Assertion : Minimum deviation for a give...

Assertion : Minimum deviation for a given prism does not depend on the refractive index `mu`, of the prism.
Reason : Deviation by a prism is given by
`delta=(i_(1) + i_(2) +A)` and does not have the term `mu`.

A

If both assertion and reason are true and\ reason is a correct explanation of the assertion

B

If both assertion and reason are true but the reason is not a correct explanation of assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and the reason provided. **Assertion:** Minimum deviation for a given prism does not depend on the refractive index `μ` of the prism. **Reason:** Deviation by a prism is given by `δ = (i₁ + i₂ + A)` and does not have the term `μ`. ### Step-by-Step Solution: 1. **Understanding Minimum Deviation:** - The minimum deviation occurs when the light ray passes symmetrically through the prism. In this case, the angles of incidence (i₁) and emergence (i₂) are equal, i.e., i₁ = i₂. 2. **Using the Formula for Deviation:** - The formula for the angle of deviation (δ) for a prism can be expressed as: \[ δ = i₁ + i₂ - A \] - At minimum deviation, since i₁ = i₂, we can denote them as 'i'. Thus, the formula simplifies to: \[ δ_{min} = 2i - A \] 3. **Relation to Refractive Index:** - The angle of incidence (i) is related to the refractive index (μ) of the prism and the angles of the prism. However, at minimum deviation, the relationship can be derived from Snell's law and the geometry of the prism. - The minimum deviation does not directly include the refractive index in its final expression, indicating that for a specific prism angle A, the minimum deviation is a function of the angles of incidence and not directly dependent on μ. 4. **Conclusion on Assertion:** - Since the minimum deviation δ_min can be expressed in terms of angles that do not include μ, the assertion is true: the minimum deviation for a given prism does not depend on the refractive index μ. 5. **Evaluating the Reason:** - The reason states that the deviation is given by `δ = (i₁ + i₂ + A)`, which is incorrect because the correct formula for deviation is `δ = (i₁ + i₂ - A)`. - Therefore, the reason is false. ### Final Conclusion: - The assertion is **true** while the reason is **false**. Hence, the correct answer is that the assertion is true but the reason is false.
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Knowledge Check

  • If the angle of minimum deviation is of 60^@ for an equilateral prism , then the refractive index of the material of the prism is

    A
    `1.41`
    B
    `1.5`
    C
    `1.6`
    D
    `1.73`
  • For thin prism angle of minimum deviation( delta ) is given by

    A
    `delta = A(1-mu)`
    B
    `delta = A((mu)/(2)-1)`
    C
    `delta = A(1-(mu)/(2))`
    D
    `delta = A(mu-1)`
  • The angle of minimum deviation produced by an equilateral prism is 46^@ The refractive index of material of the prism.

    A
    1.6
    B
    1.5
    C
    1.4
    D
    1.8
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