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A person can see clearly upto 1 m. The n...

A person can see clearly upto 1 m. The nature and power of the lens which will enable him to see things at a distance of 3 m is

A

concave, -0.66 D

B

convex, -0.66 D

C

concave, -0.33D

D

convex, -0.33D

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the nature and power of the lens required for a person who can see clearly up to 1 meter to see objects at a distance of 3 meters. Here’s a step-by-step solution: ### Step 1: Identify the Given Information - The maximum distance at which the person can see clearly (the near point) is \( d_{near} = 1 \, \text{m} \). - The distance at which the person wants to see clearly (the far point) is \( d_{far} = 3 \, \text{m} \). ### Step 2: Set Up the Lens Formula We will use the lens formula, which is given by: \[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where: - \( f \) is the focal length of the lens, - \( v \) is the image distance, - \( u \) is the object distance. ### Step 3: Assign Values to \( u \) and \( v \) - Since the object is at 3 meters, we have \( u = -3 \, \text{m} \) (the object distance is taken as negative in lens formula convention). - The image must be formed at the near point of the person, so \( v = 1 \, \text{m} \). ### Step 4: Substitute Values into the Lens Formula Now, substituting the values into the lens formula: \[ \frac{1}{f} = \frac{1}{1} - \frac{1}{-3} \] This simplifies to: \[ \frac{1}{f} = 1 + \frac{1}{3} = 1 + 0.333 = \frac{4}{3} \] ### Step 5: Calculate the Focal Length Now, we can find \( f \): \[ f = \frac{3}{4} \, \text{m} = 0.75 \, \text{m} \] ### Step 6: Calculate the Power of the Lens The power \( P \) of the lens is given by: \[ P = \frac{1}{f(\text{in meters})} \] Substituting \( f = 0.75 \, \text{m} \): \[ P = \frac{1}{0.75} = \frac{4}{3} \approx 1.33 \, \text{D} \] ### Step 7: Determine the Nature of the Lens Since the power is positive, this indicates that the lens is a **convex lens**. ### Final Answer The nature of the lens is **convex**, and the power of the lens is approximately **1.33 diopters**. ---

To solve the problem, we need to determine the nature and power of the lens required for a person who can see clearly up to 1 meter to see objects at a distance of 3 meters. Here’s a step-by-step solution: ### Step 1: Identify the Given Information - The maximum distance at which the person can see clearly (the near point) is \( d_{near} = 1 \, \text{m} \). - The distance at which the person wants to see clearly (the far point) is \( d_{far} = 3 \, \text{m} \). ### Step 2: Set Up the Lens Formula We will use the lens formula, which is given by: ...
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Knowledge Check

  • A far-sighted man can see clearly at a distance of 1.0m . The power of the lens that would make him see clearly at a distance of 0.2m is

    A
    `4 D`
    B
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    D
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    `+2D`
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    A
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    C
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