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In an n-p-n transistor 10^(10) electrons...

In an n-p-n transistor `10^(10)` electrons enter the emitter in `10^(-6)`s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.

A

`0.98,49`

B

`0.49,49`

C

`0.98,98`

D

`0.49,98`

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(I_(c))/(I_(e)),I_(c)=(98)/(100)I_(e), beta=(alpha)/(1-alpha)`
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