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In an n-p-n transistor 10^(10) electrons...

In an n-p-n transistor `10^(10)` electrons enter the emitter in `10^(-6)`s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.

A

`0.98,49`

B

`0.49,49`

C

`0.98,98`

D

`0.49,98`

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(I_(c))/(I_(e)),I_(c)=(98)/(100)I_(e), beta=(alpha)/(1-alpha)`
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Knowledge Check

  • In an npn transistor 10^(10) electrons enter he emitter in 10^(-6) s. If 2\% of the electrons are lost in the base, find the current transfer ratio and the current amplificationa factor.

    A
    0.98, 49
    B
    1.96, 98
    C
    0.49, 98
    D
    1.96, 49

  • In a n-p-n transistor 10^(10) electrons enter the emitter in 10^(-6)s . 2% of the elecrons are lost in the base. The current transfer ratio and the current amplification factor will be

    A
    `0.98,49`
    B
    `98,0.49`
    C
    `0.49,98`
    D
    `49,0.49`

  • In an n-p-n transistor, 10^(10) electrons enter the emitter in 10^(-6) s. 2% of the electrons are lost in the base. The current transfer ratio is

    A
    0.88
    B
    0.78
    C
    0.98
    D
    0.68

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