Home
Class 11
PHYSICS
Consider the equation T = 2pi sqrt ((l)/...

Consider the equation `T = 2pi sqrt ((l)/(g))` and check whether it is correct or not.

Text Solution

AI Generated Solution

To check whether the equation \( T = 2\pi \sqrt{\frac{l}{g}} \) is dimensionally correct, we need to compare the dimensions on both sides of the equation. Here’s the step-by-step solution: ### Step 1: Determine the dimension of the left-hand side (LHS) The LHS of the equation is \( T \), which represents the time period. - The dimension of time \( T \) is \([T]\). ### Step 2: Determine the dimension of the right-hand side (RHS) ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise EVALUATE YOURSELF - 1|10 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise EVALUATE YOURSELF - 2|9 Videos
  • UNITS AND MEASUREMENTS

    NARAYNA|Exercise ILLUSTRATION|49 Videos
  • TRANSMISSION OF HEAT

    NARAYNA|Exercise LEVEL-II(C.W)|27 Videos
  • VECTORS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2 pi sqrt((1)/(g)) where g is constant.What is the percentage error in T when l is increased by 1%?

Using the dimensional analysis, check whether the following equation is correct or not: T=2pisqrt(R^(3)//GM) .

Knowledge Check

  • The equation T=2pisqrt(l//g) is valid only when

    A
    the length of the pendulum is less than the radius the earth
    B
    the length of the pendulum is greater than or equal to radius by the earth
    C
    the length of pendulum is independent of the radius of the earth
    D
    length of the pendulum is equal to radius and the earth.
  • A small metallic bob of mass m of a simple pendulum of length l is suspended from a silk threas between two parallel charged plates.The electric field intensity E act vertically downwards . If bob is given a charge + q ,time period of oscillation (i) T = 2 pi sqrt((l)/((g - (qE)/(m)))) , if the lower plate is charged positively (ii) T = 2 pi sqrt((l)/((g - (qE)/(m)))) ,if the lower plate is charged negatively (iii) T = 2 pi sqrt((l)/((g + (qE)/(m)))) ,if the lower plate is charged positively (iv) T = 2 pi sqrt((l)/((g + (qE)/(m)))) , if the lower plate is charged negatively

    A
    `(i) ,(ii)`
    B
    `(i),(iii)`
    C
    `(i),(iv)`
    D
    all
  • Similar Questions

    Explore conceptually related problems

    Find the dimensions of K in the relation T = 2pi sqrt((KI^2g)/(mG)) where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

    With the usual notations , check if the following equation S_(t) = u + (1)/(2) a ( 2t -1) is dimensionally correct or not.

    The time T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.

    For the quadratic equation 2x^2-x-10=0 check whether (i) x=-2 are roots or not?

    Check whether the relation S = ut + (1)/(2) at^(2) is dimensionally correct or not , where symbols have their usual meaning .

    The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place. (a) Express 'g' in terms of T (b) What is the length of the seconds pendulum ? (Take g = 10 m s^(-2) )