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If mass (M), length (L) and force (F) ar...

If mass (M), length (L) and force (F) are considered as fundamental quantities then, find the dimensional formula for time

A

`M^(1//2)L^(-1//2)F^(1//2)`

B

`M^(-1//2)L^(-1//2)F^(1//2)`

C

`M^(1//2)L^(-1//2)F^(1//2)`

D

`M^(1//2)L^(1//2)F^(-1//2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula for time (T) in terms of mass (M), length (L), and force (F), we can follow these steps: ### Step 1: Write down the dimensional formula for force The dimensional formula for force (F) is given by: \[ F = M \cdot a \] where \( a \) (acceleration) has the dimensions \( L \cdot T^{-2} \). Therefore, the dimensional formula for force can be expressed as: \[ [F] = [M][L][T^{-2}] = M^1 L^1 T^{-2} \] ### Step 2: Rearrange the equation to express time in terms of mass, length, and force We can rearrange the equation for force to isolate time (T): \[ [F] = M^1 L^1 T^{-2} \] This can be rearranged as: \[ T^{-2} = \frac{[F]}{[M][L]} \] Taking the reciprocal gives: \[ T^2 = \frac{[M][L]}{[F]} \] ### Step 3: Take the square root to find the dimensional formula for time Now, taking the square root of both sides, we get: \[ T = \sqrt{\frac{[M][L]}{[F]}} \] This can be rewritten as: \[ T = [M]^{1/2} [L]^{1/2} [F]^{-1/2} \] ### Step 4: Write the final dimensional formula for time Thus, the dimensional formula for time (T) in terms of mass (M), length (L), and force (F) is: \[ [T] = M^{1/2} L^{1/2} F^{-1/2} \] ### Conclusion The dimensional formula for time in terms of mass, length, and force is: \[ [T] = M^{1/2} L^{1/2} F^{-1/2} \]
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Knowledge Check

  • If the energy (E), velocity (v) and force (F) are taken as fundamental quantities, then what is the dimensional formula for mass?

    A
    `E^(1)v^(2)F^(1)`
    B
    `F^(1)v^(-1)E^(1)`
    C
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    D
    `F^(1)v^(-2)E^(0)`
  • If force F, Length L and time T are chosen as fundamental quantities , the dimensioal formula for mass is

    A
    [FLT]
    B
    `[F^(-1) L^(-1) T^(-2)]`
    C
    `[F^(-2) L^(-2) T^(-2)]`
    D
    `[F^(1) L^(-1) T^(-2)]`
  • If force F , Length L and time T are chosen as fundamental quantites, the dimensional formula for Mass is

    A
    `[FLT]`
    B
    `[F^(-1) L^(-1) T^(-2)]`
    C
    `[F^(-2) L^(-2) T^(-2)]`
    D
    `[F^(1) L^(-1) T^(2)]`
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