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Calculate the enthalpies change for the ...

Calculate the enthalpies change for the reaction,
`H_(2)(g)+Cl_(2)(g)to2HCl(g)`
Given that, bond energies of H-H,Cl-Cl and H-Cl are 436, 243 and 432 kJ `mol^(-1)`

Text Solution

AI Generated Solution

To calculate the enthalpy change for the reaction \( H_2(g) + Cl_2(g) \rightarrow 2HCl(g) \), we will use the bond energies provided for the bonds broken and formed during the reaction. ### Step 1: Identify the bonds broken in the reactants In the reactants, we have: - 1 H-H bond in \( H_2 \) - 1 Cl-Cl bond in \( Cl_2 \) The bond energies are: ...
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Calculate the enthalpy change for the reaction . H_(2)(g) + Br_(2)(g) to 2HBr (g) Given that the bond energies of H-H, H-Br, and Br-Br are 435 kJ mol^(-1) , 364 kJ mol^(-1) , and 192 kJ mol^(-1) , respectively.

Calculate free energy change for the reaction, H_(2)(g)+Cl_(2)(g)to2H-Cl(g) By using the bond energy and entropy data. Bond energies of H-H,Cl-Cl and H-Cl bonds are 435kJ mol^(-1),240jK" "mol^(-1) and 430jk" "mol^(-1) respectively standard entropies of H_(2),Cl_(2) and HCl are 130.59,222.95 and 186.68 JK^(-1)" "mol^(-1) respectively.

Knowledge Check

  • In the reaction, H_(2)(g) +Cl_(2) (g) hArr 2HCl (g) :

    A
    `K_(p) ne K_(c )`
    B
    `K_(p) = K_(c )`
    C
    `K_(p) gt K_(c )`
    D
    `K_(p) lt K_(c )`

  • In the reaction, H_(2)(g) +Cl_(2) (g) hArr 2HCl (g) :

    A
    `K_(p) ne K_(c )`
    B
    `K_(p) = K_(c )`
    C
    `K_(p) gt K_(c )`
    D
    `K_(p) lt K_(c )`

  • Enthalpy change for reaction 1//2H_(2)(g)+1//2Cl_(2)(g)toHCl(g) is called :-

    A
    Enthalpy of combustion
    B
    Enthalpy of solution
    C
    Enthalpy of formation
    D
    Enthalpy of fusion

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