Calculate the enthalpies change for the reaction,
`H_(2)(g)+Cl_(2)(g)to2HCl(g)`
Given that, bond energies of H-H,Cl-Cl and H-Cl are 436, 243 and 432 kJ `mol^(-1)`

Explanation

To calculate the enthalpy change for the reaction \( H_2(g) + Cl_2(g) \rightarrow 2HCl(g) \), we will use the bond energies provided for the bonds broken and formed during the reaction.

### Step 1: Identify the bonds broken in the reactants
In the reactants, we have:
- 1 H-H bond in \( H_2 \)
- 1 Cl-Cl bond in \( Cl_2 \)

The bond energies are:
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