Home
Class 12
CHEMISTRY
An oxide of iodine contains 25.4g of iod...

An oxide of iodine contains 25.4g of iodine for 8g of oxygen. Its molecular formula will be:

A

`I_(2)O_(3)`

B

`I_(2)O`

C

`I_(2)O_(5)`

D

`I_(2)O_(7)`

Text Solution

Verified by Experts

The correct Answer is:
c
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STOICHIOMETRY (CHEMICAL FORMULAE AND EQUATIONS )

    OP TANDON|Exercise PASSAGE-2|5 Videos
  • SATURATED ALIPHATIC HYDROCARBONS

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|7 Videos
  • UNSATURATED HYDROCARBONS

    OP TANDON|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

Name an iodine containing hormone.

An oxide of iodine (I = 127 atoms) contains 42.3g of idonie and 8g of oxygen. Its formula could be

Knowledge Check

  • An oxide of iodine ( I =127) contains 25.4g of iodine and 8g of oxygen. Its formula could be

    A
    `I_(2) O_(3)`
    B
    `I_(2)O`
    C
    `I_(2)O_(5)`
    D
    `I_(2)O_(9)`
  • Ticture of iodine contains

    A
    `I_(2),KI` and `C_(2)H_(5)OH`
    B
    `I_(2)` and `C_(2)H_(5)OH`
    C
    `KI` and `C_(2)H_(5)OH`
    D
    `I_(2)` and `H_(2)O`
  • Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molecular formula=(Empirical formula) xxn n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formulae Both these formulae are calculated by using percentage composition of constituent elements. An oxide of iodine (I=127) contains 25.4 g of iodine and 8 g of oxygen. its formula could be:

    A
    `I_(2)O_(3)`
    B
    `I_(2)O`
    C
    `I_(2)O_(5)`
    D
    `I_(2)O_(7)`
  • Similar Questions

    Explore conceptually related problems

    PASSAGE-II : Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molacular formula = (Empirical formula) xxn implies n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formula. Both these formulae are calculated using percentage composition of constituent elements. An oxide of iodine (Atomic mass of I = 127 u) contains 25.4 g of iodine and 8 g of oxygen. Its formula could be :

    On analysis a certain compound was found to contain 254 g of iodine and 80 g of oxygen. The atomic mass of iodine is 127 and that of oxygen is 16. What is the formula of the compound?

    On analysis, a compound was found to contain iodine and oxygen in the ratio of 254 g iodine and 48 g of oxygen. The formula of the compound is _______ . (I = 127, O = 16)

    Tincture of iodine contains iodine and _________ .

    Oxidation states of iodine vary from