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The standard electrode potentials of Zn,...

The standard electrode potentials of Zn, Ag and Cu are -0.76, 0.80 and 0.34 volt respectively, then:

A

Ag can oxidised Zn and Cu

B

Ag can reduce `Zn^(2+)` and `Cu^(2+)`

C

Zn can reduce `Ag^(+)` and `Cu^(2+)`

D

Cu can oxidise Zn and Ag

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the standard electrode potentials of Zn, Ag, and Cu, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Standard Electrode Potentials**: - The standard electrode potentials given are: - Zn²⁺/Zn: -0.76 V - Ag⁺/Ag: +0.80 V - Cu²⁺/Cu: +0.34 V 2. **Understand the Meaning of Standard Electrode Potentials**: - The standard electrode potential indicates the tendency of a species to be reduced. A higher (more positive) value means a stronger oxidizing agent, while a lower (more negative) value indicates a stronger reducing agent. 3. **Determine the Reducing and Oxidizing Agents**: - **Reducing Agent**: The species with the lowest standard reduction potential (most negative) is the best reducing agent. Here, Zn (-0.76 V) is the best reducing agent. - **Oxidizing Agents**: The species with the highest standard reduction potential (most positive) is the best oxidizing agent. Here, Ag (+0.80 V) is the best oxidizing agent. 4. **Write the Half-Reactions**: - For Zn: \[ \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \quad (\text{oxidation}) \] - For Ag: \[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \quad (\text{reduction}) \] - For Cu: \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \quad (\text{reduction}) \] 5. **Determine Which Reactions Occur**: - Since Zn is a strong reducing agent, it can reduce both Ag⁺ and Cu²⁺. Therefore, Zn will oxidize itself while reducing Ag⁺ to Ag and Cu²⁺ to Cu. 6. **Conclusion**: - Based on the standard electrode potentials, the correct conclusion is that Zinc will reduce both Silver ions (Ag⁺) and Copper ions (Cu²⁺). Therefore, the correct answer is option C: Zinc reduces Ag⁺ and Cu²⁺. ### Final Answer: The correct answer is **C**: Zinc reduces Ag⁺ and Cu²⁺.
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A cell is prepared by dipping the Cu rod in M CuSO_(4) solution and the Zn rod in 1 M ZnSO_(4) solution . The standard reduction potentials of copper and zinc are 0.34 V and - 0 . 76 V , respectively .

Calculate the standard potential of the cell ,If the standard electrode potentials of Zn^(2+)//Zn and Ag^(+) //Ag are -0.763 V and + 0.799 V respectively .

Knowledge Check

  • The standard electrode potential of Zn^(2+)//Zn and Ag^(+)//Ag are -0.763 and +0.799V respectively. The standard potential of the cell is:-

    A
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    B
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    C
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    D
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    B
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    C
    `-1.562V`
    D
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  • The standard reduction potential of Zn^(2+)|Zn and Cu^(2+)|Cu are -0.76V and +0.34 V respectively. What is the cell e.m.f (in V) of the following cell? ((RT)/(F)=0.059) Zn//Zn^(2+)" "(0.05M)//Cu^(2+)(0.005M)//Cu

    A
    `1.1295`
    B
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    C
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    D
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