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Two faraday of electricity is passed thr...

Two faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cthode is :
(at mass of cu = 63.5 amu)

A

127 g

B

0 g

C

63.5 g

D

2 g

Text Solution

Verified by Experts

The correct Answer is:
C
Equivalent mass of copper `=("Atomic mass")/("Valency")`
`=63.5/2=31.75`
Amount of copper deposited by 2 faraday `=2xx31.75`
`=63.5 g`
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Two Faraday of electricity is passed through solution of CuSO_(4) . The mass of copper deposited at the cathode is : (Atomic mass of Cu = 63.5 amu)

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Knowledge Check

  • Two Faraday of electricity is passed through a solution of CuSO_(4) . The mass of copper deposited at the cathode is : (at mass of Cu = 63.5 amu)

    A
    2 g
    B
    127 g
    C
    0 g
    D
    63.5 g

  • Two faraday of electricity is passed through a solution of CuSO_(4) . The mass of copper deposited at the cathode is: (at mass of Cu = 63.5 amu)

    A
    `0 g`
    B
    `63.5 g`
    C
    `127 g`
    D
    `2 g`

  • Two faraday of electricity is passed through a solution of CuSO_(4) . The mass of copper deposited at the cathode is (at. Ass of Cu=63.5 amu)

    A
    0g
    B
    63.5g
    C
    2g
    D
    127g

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