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The solubility of fluorides of alkali me...

The solubility of fluorides of alkali metals in water is

A

`LiF gt NaF gt KF gt RbF gt CsF`

B

`CsF gt RbF gt KF gt NaF gt LiF`

C

`LiF gt KF gt NaF gt CsF gt RbF`

D

`CsF gt KF gt NaF gt RbF gt LiF`

Text Solution

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The correct Answer is:
To determine the solubility trend of alkali metal fluorides in water, we need to analyze the factors affecting solubility, namely lattice energy and hydration energy. ### Step-by-Step Solution: 1. **Understanding Lattice Energy and Hydration Energy**: - **Lattice Energy**: This is the energy required to separate one mole of a solid ionic compound into its gaseous ions. It is influenced by the size of the ions; smaller ions generally lead to higher lattice energy due to stronger electrostatic forces between them. - **Hydration Energy**: This is the energy released when ions are surrounded by water molecules. Smaller ions can be hydrated more effectively, leading to higher hydration energy. 2. **Analyzing the Alkali Metal Fluorides**: - The alkali metal fluorides we are considering are: Lithium Fluoride (LiF), Sodium Fluoride (NaF), Potassium Fluoride (KF), Rubidium Fluoride (RbF), and Cesium Fluoride (CsF). - Fluoride ion (F⁻) is relatively small, and thus the size of the cation (alkali metal ion) will significantly influence the lattice energy. 3. **Trend in Lattice Energy**: - As we move down the group from Lithium to Cesium, the size of the alkali metal cations increases. This leads to a decrease in lattice energy because the distance between the cations and anions increases, weakening the electrostatic attraction. - Therefore, the trend in lattice energy is: LiF > NaF > KF > RbF > CsF (decreasing). 4. **Trend in Hydration Energy**: - Hydration energy also decreases as we move down the group, but the decrease is not as pronounced as the decrease in lattice energy. Smaller cations (like Li⁺) have higher hydration energy due to their ability to attract water molecules more effectively. 5. **Comparing Lattice Energy and Hydration Energy**: - For a compound to be soluble, its hydration energy must be greater than its lattice energy. - As we move down the group, the lattice energy decreases more significantly than the hydration energy. This means that the solubility of these fluorides increases down the group. 6. **Solubility Trend**: - Based on the above analysis, the solubility trend in water for alkali metal fluorides is: - Most soluble: CsF > RbF > KF > NaF > LiF: Least soluble. ### Final Answer: The solubility of fluorides of alkali metals in water increases down the group, with cesium fluoride (CsF) being the most soluble and lithium fluoride (LiF) being the least soluble.
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(a) Why is LiF least soluble in water among the fluorides of alkali metals ? Justify the given (b) Justify the given order of mobilites of the alkali mteal cations in aqueous solution: Li lt Na^(+) lt K^(+) lt Rb^(+) lt Cs^(+) (c) Lithium is the only alkali metal which forms a nitride directly. Explain . (d) E^(@) for M^(2+)(aq)toM(s) (where M=Ca,Sr or Ba) is nearly constant. Discuss.

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Knowledge Check

  • The solubility order for alkali metal floride in water is :

    A
    `LiF lt RbF lt KF lt NaF`
    B
    `RbF lt KF lt NaF lt LiF`
    C
    `LiF gt NaF gt KF gt RbF`
    D
    `LiF lt NaF lt KF lt RbF`
  • The solubility order for alkali metal fluoride in water is :

    A
    `LiF lt RbF lt KF lt NaF`
    B
    `RbF lt KF lt NaF lt LiF`
    C
    `LiF lt NaF lt KF lt RbF`
    D
    `LiF gt NaF gt KF gt RbF`
  • The solubility order for alkali metal fluoride in water is

    A
    `LiF lt RbF lt KF lt NaF`
    B
    `RbF lt KF lt NaF lt LiF`
    C
    `LiF lt RbF lt NaF lt KF `
    D
    `LiF lt NaF lt KF lt RbF `
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