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A ball is dropped on a horizontal surfac...

A ball is dropped on a horizontal surface from height h. If it rebounds upto `h/2` after first collision then coefficient of restitution between ball and surface is

A

`1 sqrt2`

B

`1/2`

C

`1/4`

D

`1/2 + sqrt2`

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The correct Answer is:
To find the coefficient of restitution (e) between a ball and a horizontal surface when the ball is dropped from a height \( h \) and rebounds to a height of \( \frac{h}{2} \), we can follow these steps: ### Step 1: Determine the velocity of the ball just before impact When the ball is dropped from height \( h \), we can use the third equation of motion to find the velocity just before it hits the ground. The equation is: \[ v^2 = u^2 + 2gh \] Here, \( u = 0 \) (initial velocity), \( g \) is the acceleration due to gravity, and \( h \) is the height from which the ball is dropped. Substituting the values, we get: \[ v^2 = 0 + 2gh \implies v = \sqrt{2gh} \] This velocity \( v \) is the velocity of approach (\( V_A \)) just before the ball hits the ground. ### Step 2: Determine the velocity of the ball just after rebound After rebounding to a height of \( \frac{h}{2} \), we can again use the third equation of motion to find the velocity just after the ball leaves the ground. The equation is: \[ v^2 = u^2 - 2gh \] In this case, the final velocity \( v = 0 \) (at the peak of the rebound), and we need to find the initial velocity \( u \) just after the rebound. The height is \( \frac{h}{2} \). Substituting the values, we have: \[ 0 = u^2 - 2g\left(\frac{h}{2}\right) \implies u^2 = gh \implies u = \sqrt{gh} \] This velocity \( u \) is the velocity of separation (\( V_S \)) just after the ball rebounds. ### Step 3: Calculate the coefficient of restitution The coefficient of restitution \( e \) is defined as the ratio of the velocity of separation to the velocity of approach: \[ e = \frac{V_S}{V_A} \] Substituting the values we found: \[ e = \frac{\sqrt{gh}}{\sqrt{2gh}} = \frac{1}{\sqrt{2}} \] ### Final Answer The coefficient of restitution between the ball and the surface is: \[ e = \frac{1}{\sqrt{2}} \] ---

To find the coefficient of restitution (e) between a ball and a horizontal surface when the ball is dropped from a height \( h \) and rebounds to a height of \( \frac{h}{2} \), we can follow these steps: ### Step 1: Determine the velocity of the ball just before impact When the ball is dropped from height \( h \), we can use the third equation of motion to find the velocity just before it hits the ground. The equation is: \[ v^2 = u^2 + 2gh \] ...
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NARAYNA-WORK , ENERGY & POWER -EXERCISE - 1 (C.W)
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  2. A vehicle is travelling with uniform speed along a concave road of rad...

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  3. A car is travelling along a flyover bridge which is a part of vertical...

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  4. A very small particle rests on the top of a hemisphere of ra...

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  5. Two steel balls A and B of mass 10 kg and 10 g rolls towards each othe...

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  6. Two identical balls moving in opposite direction with speed 20 m/s and...

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  7. A ball of mass 5 kg moving with speed 8 m/s collides head on with anot...

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  8. A ball is dropped on a horizontal surface from height h. If it rebound...

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  9. A ball of 4 kg mass moving with a speed of 3ms^(-1) has a head on elas...

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  10. A ping-pong ball strikes a wall with a velocity of 10 ms^(-1). If the ...

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  11. Two identical balls collide head on. The initial velocity of one is 0....

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  12. A truck of mass 15 tons moving with 1 ms^(-1) collides with a stationa...

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  13. In the above problem the total KE before collision is

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  14. In the above problem loss of KE during collision is

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  15. A bullet of mass 'x' moves with a velocity y, hits a wooden block of m...

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  16. A railway truck of mass 16000 kg moving with a velocity of 5ms^(-1) st...

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  17. A ball falls from a height of 10m on to a horizontal plane. If the coe...

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  18. A ball is dropped from a height of 3m. If coefficient of restitution b...

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  19. A glass sphere of mass 5mg, falls from a height of 3 meters on to a ho...

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  20. A particle falls from a height h upon a fixed horizontal plane and reb...

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