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Two forces each numerically equal to 5N ...

Two forces each numerically equal to 5N are acting as shown in the figure, then find resultant of these two vectors.

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To find the resultant of two forces each numerically equal to 5N acting at an angle of 120 degrees to each other, we can use the vector addition formula for two vectors. Given: - Magnitude of each force, \( F_1 = F_2 = 5 \, \text{N} \) - Angle between the forces, \( \theta = 120^\circ \) We use the formula for the resultant of two vectors: \[ R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2 \cos \theta} \] ...
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Knowledge Check

  • Two forces, each numerically equal to 5 N, are acting as shown in the figure. Then the resultant is

    A
    2.5 N
    B
    5 N
    C
    `5sqrt(3)N`
    D
    10 N
  • Two forces , each numerically equal to 10 dyne are acting as shown in the following figure Their resultant is :

    A
    10 dyne
    B
    20 dyne
    C
    `10sqrt(3)` dyne
    D
    5 dyne
  • Two forces each numerically equal to 10 dynes are acting as shown in the following figure, then their resultant is -

    A
    10 dynes
    B
    20 dynes
    C
    `10sqrt(3)` dynes
    D
    5 dynes
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