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Find out the angle made by (hati+hatj) v...

Find out the angle made by `(hati+hatj)` vector from X and Y axes respectively.

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`a=sqrt(a_(x)^(2)+a_(y)^(2))=sqrt(1^(2)+1^(2))=sqrt(2)`
`cos alpha=(a_(x))/(a)=(1)/sqrt(2) therefore alpha=45^(@)`
`cos beta=(a_(y))/(a)=(1)/sqrt(2) therefore beta=45^(@) hati+hatj` is at bisector of X and Y axes.
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