Derive an expression for the velocity of pulse in a in stretched in string under a tension `T` and `mu` is the mass per unit length of the sting.

Answer

The broad view of the pulse under the tension `T` is given by
`(##RES_WFPM_PHY_XI_C05_E01_014_A01##)`
As; `2T sin (theta)/(2) = dm (v^(2))/(R)`
`rArr 2T(theta)/(2) = ((m)/(l)). Rtheta (v^2))/(R)`
`rArr v = sqrt((T)/(mu))`
where `mu = (m)/(l)`, is the mass per unit length of the string also known as the linear mass density.