The standard oxidation potential of `Zn` referred to SHE is 0.76 V and that of Cu is `-0.34V` at `25^(@)C` when excess of `Zn` is added to `CuSO_(4)`, Zn displaces `Cu^(2+)` till equilibrium is reached. What is the approx ratio of `Zn^(2+)` to `Cu^(2+)` ios at equilibrium?

Answer

`[Zn^(2+)]//[Cu^(2+)]=2xx10^(37)`