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For a concave lens of focal length f, th...

For a concave lens of focal length f, the relation between object and image distance u and v, respectively, from its pole can best be represented by (u = v is the reference line) :

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To solve the problem regarding the relationship between object distance \( u \) and image distance \( v \) for a concave lens with focal length \( f \), we will follow these steps: ### Step-by-Step Solution: 1. **Understand the Sign Convention**: - For a concave lens, the focal length \( f \) is considered negative. - The object distance \( u \) is also taken as negative since the object is placed on the same side as the incoming light. - The image distance \( v \) is negative as well since the image formed by a concave lens is virtual and located on the same side as the object. 2. **Lens Formula**: - The lens formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] - Rearranging this, we can express \( v \) in terms of \( u \): \[ \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \] - This can be rewritten as: \[ v = \frac{fu}{u + f} \] 3. **Graphical Representation**: - To analyze the relationship graphically, we can plot \( v \) against \( u \). - The equation \( v = \frac{fu}{u + f} \) indicates that as \( u \) approaches infinity (the object moves far away), \( v \) approaches \( f \) (which is negative). 4. **Finding the Tangent**: - At the origin (where \( u = 0 \)), we can find the slope of the curve to determine the tangent. - The derivative \( \frac{dv}{du} \) can be calculated to find the slope at \( u = 0 \): \[ \frac{dv}{du} = \frac{f}{(u + f)^2} \] - Evaluating this at \( u = 0 \): \[ \frac{dv}{du} \bigg|_{u=0} = \frac{f}{f^2} = \frac{1}{f} \] 5. **Conclusion**: - The tangent at the origin corresponds to the line \( v = u \) since it has a slope of 1. - The curve will not intersect the line \( v = u \) except at the origin, confirming that the relationship between \( u \) and \( v \) for a concave lens does not allow for real intersections. ### Final Answer: The correct representation of the relationship between object distance \( u \) and image distance \( v \) for a concave lens is that the curve approaches the line \( v = u \) but does not intersect it except at the origin.
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Knowledge Check

  • In a convex lens of focal length F, the minimum distance between an object and its real image mus be -

    A
    3F
    B
    4F
    C
    `(3)/(2)F`
    D
    `2 f`
  • A convex lens of focal length f produces a real image m times the size of an object, then the distance of the object from the lens is

    A
    (m + 1)f
    B
    (m - 1)f
    C
    `((m+1)/m)f`
    D
    `((m-1)/m)f`
  • A concave lens of focal length f produces an image (1/x) of the size of the object, the distance of the object from the lens is

    A
    `(x-1)f`
    B
    `(x+1)f`
    C
    `{(x-1)//x]f`
    D
    `{(x+1)//x}f`
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    For a concave mirror of focal length f, image is 2 times larger. Then the object distance from the mirror can be

    A convex lens of focal length f produces a virtual image n times the size of the object. Then the distance of the object from the lens is