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How much mass (kg) of CaCO(3) is needed ...

How much mass (kg) of `CaCO_(3)` is needed to produce 336 kg of Cao ? [Given : % yield of reaction = 60]

A

`10^(3)`

B

`10^(2)`

C

900

D

800

Text Solution

Verified by Experts

The correct Answer is:
A
`CaCO_(3)(s)rarrunderset(336kg)(CaO(s))+CO_(2)1g`
Moles of CaO = `(336)/(56)xx10^(3)=6xx10^(3)`
Mass of `CaCO_(3)` required `=6xx10^(3)xx(100)/(60)xx100=10^(3)kg`
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Knowledge Check

  • How many kg of CaCo_(3) [Mol. Wt = 100g mol e^(-1)] is needed to produce 336 kg of CaO [Mol wt = 56g mol^(-1)] if % yield of the reaction given is 60%. CaCO_(3)(s) rightarrow CaO(s) + CO_(2)(g)

    A
    `10^(3)`
    B
    `10^(2)`
    C
    900
    D
    800

  • The following sequence of reaction occurs in commical production of aqueous nitric acid. NH_(3)(g)+O_(2)(g) rarr NO(g)+H_(2)O(l) NO(g)+O_(2)(g)rarr NO_(2)(g) NO_(2)(g)+H_(2)O(l) rarr HNO_(3)(aq)+NO(g) In an industry , 378 kg of HNO_(3) was required to be produced. If % yield of reaction(i),(ii) and (iii) is 85% , 60% and 50% respectively , then mass (kg) of NH_(3) required is : [NO produced in reaction(iii) is not re-used in reaction-(ii)]

    A
    30
    B
    600
    C
    6000
    D
    300

  • How much CaCO_(3) will give 2.2 g CO_(2)?

    A
    10 g
    B
    50 g
    C
    5 g
    D
    15 g

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