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How much mass (kg) of CaCO(3) is needed ...

How much mass (kg) of `CaCO_(3)` is needed to produce 336 kg of Cao ? [Given : % yield of reaction = 60]

A

`10^(3)`

B

`10^(2)`

C

900

D

800

Text Solution

Verified by Experts

The correct Answer is:
A
`CaCO_(3)(s)rarrunderset(336kg)(CaO(s))+CO_(2)1g`
Moles of CaO = `(336)/(56)xx10^(3)=6xx10^(3)`
Mass of `CaCO_(3)` required `=6xx10^(3)xx(100)/(60)xx100=10^(3)kg`
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