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Write the equilibrium constant of the r...

Write the equilibrium constant of the reaction
`C(s)+H_(2)O(g)hArrCO(g)+H_(2)(g)`

Text Solution

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`K_(p)=(P_(CO(g)).P_(H_(2)(g)))/(P_(H_(2)O(g)))
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The equilibrium constant for the reactions have been measured at 823 K. CoO(s) + H_(2)(g) hArr Co(s) + H_(2)O(g) , K = 67 CoO(s) + CO(g) hArr Co(s) + CO_(2) (g) , K = 490. From the data, calculate the equilibrium constant for the reaction. CO_(2)(g) +H_(2) (g) hArr CO(g) + H_(2)O (g)

If 2H_(2)O_((g))hArr2H_(2(g))+O_(2(g)), K_(1)=2.0xx10^(-13) 2CO_(2(g))hArr2CO_((g))+O_(2(g)), K_(2)=7.2xx10^(-12) Find the equilibrium constant for the reaction CO_(2(g))+H_(2(g))hArrCO_((g))+H_(2)O_((g))

Knowledge Check

  • The equilibrium constant for the reaction CO(g) + H_(2)O(g)hArrCO_(2)(g) + H_(2)(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H_(2) (g)] and 90 gm of steam is initially taken. What is the equilibrium concentration of H_(2)(g) at equilibrium (mole/L) ?

    A
    1.75
    B
    3.5
    C
    1.5
    D
    0.75

  • If CoO(s)+H_2(g)hArr Co(s)+H_2O(g), K_1=60 CoO(s)+CO(g)hArrCo(s)+CO_2(g), K_2=180 then the equilibrium constant of the reaction CO_2(g)+H_2(g)hArrCO(g)+H_2O(g) will be

    A
    `0.44`
    B
    `0.11`
    C
    `0.22`
    D
    `0.33`

  • The equilibrium constant for the following reactions at 1400 K are given. 2H_(2)O(g)hArr2H_(2)(g) + O_(2)(g) , K_(1)=2.1×x10^(-13) 2CO_(2)(g) hArr2CO(g)+O_(2)(g),K_(2) = 1.4 x× 10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g) + CO_(2)(g)hArrCO(g) + H_(2)O(g) is

    A
    2.04
    B
    2.6
    C
    8.4
    D
    20.5

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    Calculate the equilibrium constant for the reaction, H_(2(g))+CO_(2(g))hArrH_(2)O_((g))+CO_((g)) at 1395 K , if the equilibrium constants at 1395 K for the following are: 2H_(2)O_((g))hArr2H_(2)+O_(2(g)) ( K_(1)=2.1xx10^(-13) ) 2CO_(2(g))hArr2CO_((g))+O_(2(g)) ( K_(2)=1.4xx10^(-12) )

    Form the given data of equilibrium constants of the following reactions: CuO(s)+H_(2)(g)hArrCu(s)+H_(2)O(g),K=67 CuO(s)+CO(g)hArrCu(s)+CO_(2)(g),K=490 Calculate the equilibrium constant of the reaction, CO_(2)(g)+H_(2)(g)hArrCu(s)+CO_(2)(g)+H_(2)O(g)

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