The equation of the curves through the point (1, 0) and whose slope is `(y-1)/(x^2+x)` is

The equation of the curve through the point ( 1,2) and whose slope is (y-1)/(x^(2) + x) , is

The equation of the curve through the point (1,0), whose slope is (y-1)/(x^(2)+x)

The equation of the curve through the point (1,1) and whose slope is (2ay)/(x(y-a)) is

The equation of the curve through the point (3,2) and whose slope is (x^(2))/(y+1), is (A)1(B)2 (C) 3(D)4

Equation of the curve passing through the point (4,3) and having slope is (y)/(2) at a point (x,y) on it is

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))

Find the equation of the curve passing through the point (1,1) whose differential equation is xdy=(2x^(2)+1)dx(x!=0)