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If tangent to curve 2y^3 = ax^2+ x^3 at...

If tangent to curve `2y^3 = ax^2+ x^3` at point (a, a) cuts off intercepts `alpha, beta` on co-ordinate axes, where `alpha^2 + beta^2=61`, then the value of 'a' is equal to (A) 20 (B) 25 (C) 30 (D)-30

A

`20`

B

`25`

C

`30`

D

`-30`

Text Solution

Verified by Experts

The correct Answer is:
C, D
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