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An inductor (L = (1)/(100 pi) H), a capa...

An inductor `(L = (1)/(100 pi) H)`, a capacitor `(C = (1)/(500 pi) F)` and a resistance `(3 Omega)` is connected in series with an AC voltage source as shown in the figure. The voltage of the AC source is given as `V = 10 cos(100 pi t)` volt. What will be the potential difference between A and B ?

A

`8cos(100pit-127^(@))"volt"`

B

`8cos(100pit-53^(@))"volt"`

C

`8cos(100pit-37^(@))"volt"`

D

`8cos(100pit+37^(@))"volt"`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • An inductor X_(L) = 2 Omega ) , a capacitor ( X_(C) = 8 Omega ) and a resistance (R = 8 Omega ) are connected in series with an AC source . The voltage output of AC source is given by V = 10 cos(100 pi t) The instantaneous potential difference between points A and B, when the applied voltage is 3/5th of the maximum value of applied voltage is

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    D
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  • An inductor (X_(L) = 2 Omega) a capacitor (X_(C ) = 8 Omega) and a resistance (8 Omega) are connected in series with an ac source. The voltage output of A.C source is given by v = 10 cos 100 pi t . The instantaneous p.d. between A and B when is half of the voltage output from source will be:

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  • An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?

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