An inductor `(L = (1)/(100 pi) H)`, a capacitor `(C = (1)/(500 pi) F)` and a resistance `(3 Omega)` is connected in series with an AC voltage source as shown in the figure. The voltage of the AC source is given as `V = 10 cos(100 pi t)` volt. What will be the potential difference between A and B ?
An inductor X_(L) = 2 Omega ) , a capacitor ( X_(C) = 8 Omega ) and a resistance (R = 8 Omega ) are connected in series with an AC source . The voltage output of AC source is given by V = 10 cos(100 pi t) The instantaneous potential difference between points A and B, when the applied voltage is 3/5th of the maximum value of applied voltage is
An inductor (X_(L) = 2 Omega) a capacitor (X_(C ) = 8 Omega) and a resistance (8 Omega) are connected in series with an ac source. The voltage output of A.C source is given by v = 10 cos 100 pi t . The instantaneous p.d. between A and B when is half of the voltage output from source will be:
An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?
An inductor 200 mH, capacitor 500mu F and resistor 10 Omega are connected in series with a 100 V variable frequency ac source. What is the frequency at which the power factor of the circuit is unity?
A capacitance of ((10^(-3))/(2pi))F and an inductance of [(100)/(pi)]mH and a resistance of 10Omega are connected in series with an AC voltage source connected in series with an AC voltage source of 220V , 50Hz . The phase angle of the circuit is
A multimeter reads a voltage of a certain A.C. source as 100V . What is the peak value of voltage of A.C. source?
A 0.21 H inductor and a 12 Omega resistance are connected in series to a 220 V, 50 Hz ac source. the phase angle between the current and the source voltage is
A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find amplitude of the voltage across the inductor.
The voltage of A.C source varies with tiem according equation. V = 120 sin 100 pi t cos 100 pi t .Then the frequency of source is
The voltage of an AC source varies with time according to the relation: E = 120 sin 100 pi t cos 100 pi t V . What is the peak voltage of the source?
