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10^(-2) mole of NaOH was added to 10 lit...

`10^(-2)` mole of `NaOH` was added to `10 litres` of water. The `pH` will change by

A

4

B

3

C

11

D

7

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • 10^(-6) mole of KOH is dissolved in 10 litres of water. The pH of the solution is

    A
    12
    B
    2
    C
    3
    D
    11

  • The pH of a buffer is 6.745 . When 0.01 mole of NaOH is added to 1 litre of it, the pH changes to 6.832 . Its buffer capacity is

    A
    `0.187`
    B
    `0.115`
    C
    `0.076`
    D
    `0.896`

  • When 0.01 moles of NaOH are added to 1 litre of a buffer solution , its pH changes from 4.745 to 4.832. The buffer capacity is

    A
    0.0115
    B
    11.5
    C
    0.115
    D
    None

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    K_(sp) of AgCl in water at 25^(@)C is 1.8xx10^(-10) . If 10^(-5) mole of Ag^(+) ions are added to this solution. K_(sp) will be:

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