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If `(x , y)` and `(x ,y)` are the coordinates of the same point referred to two sets of rectangular axes with the same origin and it `u x+v y ,` where `u` and `v` are independent of `xa n dy` , becomes `V X+U Y ,` show that `u^2+v^2=U^2+V^2dot`

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To solve the problem, we need to show that if \( u x + v y \) becomes \( V X + U Y \) when coordinates are transformed from \( (x, y) \) to \( (X, Y) \) due to a rotation of axes, then \( u^2 + v^2 = U^2 + V^2 \). ### Step-by-Step Solution: 1. **Understanding the Coordinate Transformation**: When we rotate the axes by an angle \( \theta \), the new coordinates \( (X, Y) \) can be expressed in terms of the old coordinates \( (x, y) \) as follows: \[ X = x \cos \theta + y \sin \theta ...
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If (x, y) and (X, Y) be the coordinates of the same point referred to two sets of rectangular axes with the same origin and if ux + vy , when u and v are independent of X and Y become VX + UY, show that u^(2)+v^(2)=U^(2)+V^(2) .

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Knowledge Check

  • If (x,y) and (X,Y) be the coordinates of the same point referred to two sets of rectangular axes with the same origin and if ax+by becomes pX+qY, where a,b are independent of x,y, then

    A
    `a^(2)-b^(2)=p^(2)-q^(2)`
    B
    `a^(2)+b^(2)=p^(2)+q^(2)`
    C
    `a^(2)+p^(2)=b^(2)+q^(2)`
    D
    `a^(2)b^(2)=p^(2)q^(2)`
  • Let X and Y be two variables with the same variance and let U=X+Y,V=X-Y then cov (U, V) is equal to

    A
    cov (X, Y)
    B
    0
    C
    1
    D
    `-1`
  • If x and y are uncorrelated variables and if U=x+y and V=x-y, then e(u,v) is equal to

    A
    `(sigma x^(2)+sigma^(2))/(sigma x^(2)-sigmay^(2))`
    B
    `(sigma x^(2)-sigma y^(2))/(sigma x^(2)+sigma y^(2))`
    C
    `(sigma x^(2)+sigma y^(2))/(sigma x sigma y)`
    D
    `(sigma x sigma y)/(sigma x^(2)+sigma y^(2))`
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