Home
Class 12
MATHS
Let complex number 'z' satisfy the inequ...

Let complex number 'z' satisfy the inequality `2 le | x| le 4`. A point P is selected in this region at random. The probability that argument of P lies in the interval `[-pi/4,pi/4]` is `1/K`, then K =

Text Solution

Verified by Experts

The correct Answer is:
4
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • COMPLEX NUMBERS

    VK JAISWAL|Exercise EXERCISE-4:MATCHING TYPE PROBLEMS|3 Videos

  • CIRCLE

    VK JAISWAL|Exercise Exercise - 5 : Subjective Type Problems|13 Videos

  • COMPOUND ANGLES

    VK JAISWAL|Exercise Exercise-5 : Subjective Type Problems|31 Videos

Similar Questions

Explore conceptually related problems

Solve the inequation 2le|x-3|le4

The complex number z satisfying the condition arg{(z-1)/(z+1)}=(pi)/(4) lies on

Knowledge Check

  • Number of intergers satisfying the inequality x^4- 29x^2+100 le 0 is

    A
    2
    B
    4
    C
    6
    D
    8

  • Let z be a complex number satisfying |z+16|=4|z+1| . Then

    A
    `|z|=4`
    B
    `|z|=5`
    C
    `|z|=6`
    D
    `3 lt |z| lt68`

  • Let z be a complex number satisfying 1/2 le |z| le 4 , then sum of greatest and least values of |z+1/z| is :

    A
    `65/4`
    B
    `65/16`
    C
    `17/4`
    D
    17

    • Similar Questions

    Explore conceptually related problems

    Prove that the least positive value of x, satisfying tan x=x+1, lies in the interval ((pi)/(4),(pi)/(2))

    If |a|=3 and -1 le k le 2 , then |k a| lies in the interval

    Among the complex numbers z satisfying the condition | z + 1 - i| le 1 then number having the least positive argument is

    Let z be a complex number satisfying | z - 5 i | le 1 such that amp z is minimum . Then z is equal to

    The number of solutions of 2 cosx=|sinx|, 0 le x le 4 pi, is

    Home
    Profile