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The number N=6^(log(10)40). 5^(log(10)36...

The number `N=6^(log_(10)40). 5^(log_(10)36)` is a natural number ,Then sum of digits of N is :

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The correct Answer is:
9
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Knowledge Check

  • If log_(10)3=0*477 , the number of digits in 3^(40) is

    A
    `18`
    B
    `19`
    C
    `20`
    D
    `21`

  • The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

    A
    5
    B
    7
    C
    9
    D
    10

  • If log_(10)2= 0.30103, log_(10)3= 0.47712 , then the number of digits in 3^(12) xx 2^(8) is

    A
    6
    B
    5
    C
    8
    D
    9

    • Similar Questions

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    * if log_(10)3=0.4771 then the number of digits in 3^(40) is =

    If the sum of the digits of a number (10^(n)-1) is 4707, where n is a natural number,then the value of n is :

    Find the number of all 6-digit natural numbers such that the sum of their digits is 10 and each of the digits 0,1,2,3 occurs at least once in them.

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