Twelve balls are distribute among three boxes. The probability that the first box contains three balls is a.`(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))`

Twelve balls are distributed among three boxes,find the probability that the first box will contains three balls.

If 8 balls are distributed at random among three boxes,what is the probability that the first box would contain 3 balls?

The probability that when 12 distinct balls are distributed among three distinct boxes, the first will contain exactly three balls is (A) (2^(9))/(3^(12)) (B) (^(12)C_(3)*2^(9))/(9^(6)) (C) (^(12)C_(3)*2^(12))/(3^(12)) (D) (^(12)C_(3)*3^(9))/(3^(12))

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

If 12 identical balls are to be placed in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is :

In how many ways can we put 12 different balls in three different boxes such that first box contains exactly 5 balls.

If 10 different balls are to be placed in 4 distinct boxes at random, then the parobability that two of these boxes contain exactly 2 and 3 balls is :