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Twelve balls are distribute among three boxes. The probability that the first box contains three balls is a.`(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))`

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Knowledge Check

  • 12 balls are keeped in three bags. The probability that there are 3 balls in first bag is:

    A
    `110/9(2/3)^(10)`
    B
    `110/9(3/2)^(10)`
    C
    `(.^(12)C_(3))/(3^(12))`
    D
    `(.^(12)C_(3))/(12^(3))`
  • If 12 identical balls are to be placed randomly in 3 identical boxes, then the probability that one of the boxes contains exactly 3 balls is

    A
    `4/19`
    B
    `55/3(2/3)^(11)`
    C
    `((428)^(12)C_(3))/(3^(11))`
    D
    `5/19`
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