Home
Class 12
CHEMISTRY
In PO(4)^(3-) ion, the effective charge ...

In `PO_(4)^(3-)` ion, the effective charge on each oxygen atom and P-O bond order respectively are

A

`-0.75, 1.25`

B

`-0.75 , 1.0`

C

`-0.75 , 0.6`

D

`-3, 1.25`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the effective charge on each oxygen atom and the bond order of the P-O bond in the \( PO_4^{3-} \) ion, we can follow these steps: ### Step 1: Draw the Lewis Structure 1. **Count the total number of valence electrons**: - Phosphorus (P) has 5 valence electrons. - Each oxygen (O) has 6 valence electrons, and there are 4 oxygens. - The ion has a charge of -3, which means we add 3 more electrons. - Total = \( 5 + (4 \times 6) + 3 = 5 + 24 + 3 = 32 \) valence electrons. 2. **Arrange the atoms**: - Place phosphorus in the center and surround it with four oxygen atoms. 3. **Distribute the electrons**: - Start by forming single bonds between P and each O. This uses 8 electrons (4 bonds). - Distribute the remaining electrons to satisfy the octet rule for oxygen. 4. **Form double bonds**: - To minimize formal charges, we can form one double bond between P and one O, while the other three O atoms will carry a negative charge. ### Step 2: Calculate the Effective Charge on Each Oxygen Atom 1. **Identify the charges**: - In the structure, one oxygen is double bonded to phosphorus (neutral) and the other three oxygens are single bonded with a -1 charge each. 2. **Distribute the total charge**: - The total negative charge of -3 is distributed among the four oxygen atoms. - The charge on the double-bonded oxygen is 0, while the three single-bonded oxygens each have a charge of -1. 3. **Calculate the effective charge**: - The effective charge on each of the three negatively charged oxygens is \( -1 \). - The effective charge on the double-bonded oxygen is \( 0 \). ### Step 3: Calculate the Bond Order 1. **Identify the bonds**: - In the Lewis structure, we have one P=O double bond and three P-O single bonds. 2. **Count the total number of bonds**: - There are 5 bonds in total: 1 double bond (counted as 2) and 3 single bonds (counted as 3). 3. **Determine the number of resonating structures**: - The resonance structures can be drawn by moving the double bond among the four oxygen atoms. There are 4 main resonance structures. 4. **Calculate the bond order**: - Bond order is calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonds in conjugation}}{\text{Total number of resonating structures}} = \frac{5}{4} = 1.25 \] ### Final Answers - The effective charge on each oxygen atom is: - For three oxygens: -1 - For one oxygen: 0 - The bond order of the P-O bond is 1.25.
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

In PO_4^(3-) , the formal charge on each oxygen atom and the P - O bond order respectively are

In PO_(4)^(3-) the formal charge on the each oxygen atom and the P-O bond order respectively are

Knowledge Check

  • In PO_4^(3-) ion, the formal charge on each oxygen atom and P-O bond order respectively are

    A
    -1.0, +0.75
    B
    -0.75, +1.25
    C
    - 0.75, +1.0
    D
    - 0.75, +0.75
  • In PO_(4)^(3-) , the formal charge on each oxygen atom and the P-O bond order respectively are

    A
    `- 0.75, 0.6`
    B
    `-0.75,1.0`
    C
    `-0.75,1.25`
    D
    `-3,1.25`
  • In PO_(4)^(3-) , the formal change on each oxygen atom and the P-O bond order respectively are

    A
    `-0.75.06`
    B
    `-0.75.1.0`
    C
    `-0.75,1.25`
    D
    `-3,1.25`
  • Similar Questions

    Explore conceptually related problems

    In PO_(4)^(3-) ion, the formal charge on the oxygen atom of P-O bond is

    In PO_(4)^(3-) ion the formal charge on the oxygen atom of P-O bond is

    In PO_(4)^(3-) the formal charge on each O-atom and P-O bond order respectively are .

    In NO_(3)^(-) ion the formal charge on the oxygen atom of N-O bond is

    In H_(3)O^(+) the formal charge on the oxygen atom is :