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A : C("diamond") rightarrow C("graphite"...

A : `C_("diamond") rightarrow C_("graphite")`
`Delta H and Delta U` are same for this reaction.
R: Entropy increases during the conversion of diamond to graphite.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion , then mark (1)

B

If both Assertion & Reason are true and the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false, then mark (3)

D

If both Assertion is true statement but Reason is false, then mark (3)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step 1: Analyze the Assertion (A) The assertion states that the enthalpy change (ΔH) and the internal energy change (ΔU) are the same for the reaction: \[ \text{C (diamond)} \rightarrow \text{C (graphite)} \] **Explanation:** - The relationship between ΔH and ΔU is given by the equation: \[ \Delta H = \Delta U + \Delta n_g RT \] where \( \Delta n_g \) is the change in the number of moles of gas. - In this reaction, there are no gaseous reactants or products, which means \( \Delta n_g = 0 \). - Therefore, the equation simplifies to: \[ \Delta H = \Delta U \] - This confirms that the assertion is true. ### Step 2: Analyze the Reason (R) The reason states that entropy increases during the conversion of diamond to graphite. **Explanation:** - Diamond has a more ordered structure due to its tetrahedral arrangement of carbon atoms, forming a strong covalent network. - Graphite, on the other hand, has a layered structure with weaker van der Waals forces between the layers, making it less ordered. - As a result, the transition from diamond to graphite leads to an increase in disorder, which corresponds to an increase in entropy (ΔS > 0). ### Step 3: Conclusion - The assertion (A) is true: ΔH and ΔU are the same for the reaction. - The reason (R) is also true: Entropy increases during the conversion of diamond to graphite. ### Final Statement Both the assertion and the reason are true, but the reason does not explain the assertion.
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Knowledge Check

  • C("diamond")toC("Graphite") , DeltaH=-ve . Then shows that

    A
    Graphite is more stable than diamond
    B
    Graphite has more energy than diamond
    C
    Both are equally stable
    D
    Stability cannot be predicted
  • For the transition C_("(diamond)") rarr C_("(graphite)"), DeltaH=-1.5 kJ . It follows that

    A
    Graphite is stable than diamond
    B
    Diamond is stable than graphite
    C
    Graphite is endothermic substance
    D
    Diamond is exothermic substance
  • For the transition C (diamond) rarr C (graphite), Delta H = - 1.5 kJ it follows that

    A
    diamond is exothermic
    B
    graphite is endothermic
    C
    graphite is more stable than diamond
    D
    diamond is more stable than graphite
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