If solute and solvent interactions are more than solute- solute and solvent -solvent interactions then

Options

A. It is ideal solution
B. It is non-ideal solution with positive deviation
C. It is non-ideal solution with negative deviation
D. Can't predicted

Answer

To solve the question, we need to analyze the interactions between solute and solvent, as well as the implications of those interactions on the behavior of the solution according to Raoult's Law.

### Step-by-Step Solution:

1. **Understanding Interactions**:
- In a solution, there are three types of interactions: solute-solute, solvent-solvent, and solute-solvent.
- The question states that the interactions between solute and solvent are stronger than the interactions between solute-solute and solvent-solvent.

2. **Implication of Stronger Solute-Solvent Interactions**:
- When solute-solvent interactions are stronger, it means that the molecules of the solute and solvent are more attracted to each other than they are to themselves.
- This leads to a situation where the overall energy of the system is lower due to the formation of stronger bonds between solute and solvent.

3. **Raoult's Law**:
- According to Raoult's Law, the partial vapor pressure of a component in a solution is proportional to its mole fraction in the liquid phase.
- For component A (solute), the partial pressure \( P_A \) is given by:
\[ P_A = P^0_A \cdot x_A \]
- For component B (solvent), the partial pressure \( P_B \) is:
\[ P_B = P^0_B \cdot x_B \]
- The total pressure \( P_t \) of the solution is:
\[ P_t = P_A + P_B = P^0_A \cdot x_A + P^0_B \cdot x_B \]

4. **Determining the Type of Deviation**:
- If the solute-solvent interactions are stronger, the vapor pressures of the components will be lower than expected based on Raoult's Law. This is because the stronger interactions make it harder for the molecules to escape into the vapor phase.
- Therefore, the total pressure \( P_t \) will be less than what is predicted by Raoult's Law for an ideal solution.

5. **Conclusion**:
- Since the total pressure is lower than expected, this indicates a **negative deviation** from Raoult's Law.
- Thus, if solute and solvent interactions are stronger than solute-solute and solvent-solvent interactions, the solution exhibits a **negative deviation**.

### Final Answer:
If solute and solvent interactions are more than solute-solute and solvent-solvent interactions, then the solution exhibits a **negative deviation** from Raoult's Law.