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A: Boiling point of 0.1 M solution of Na...

A: Boiling point of 0.1 M solution of NaCl is higher than that of 0.1 M solution of urea.
R: Greater the value of Van't Hoff factor, greater the elevation in boiling point of solution containing non volatile solute.

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The correct Answer is:
To solve the question, we need to analyze the two assertions and their relationship to each other regarding the boiling points of solutions. ### Step-by-Step Solution: 1. **Understanding the Assertion (A)**: - The assertion states that the boiling point of a 0.1 M solution of NaCl is higher than that of a 0.1 M solution of urea. - NaCl is an ionic compound that dissociates in solution to produce ions, while urea is a non-electrolyte that does not dissociate. 2. **Dissociation of NaCl**: - When NaCl dissolves in water, it dissociates into two ions: Na⁺ and Cl⁻. - Therefore, for a 0.1 M solution of NaCl, the effective concentration of particles in solution is 0.1 M Na⁺ + 0.1 M Cl⁻ = 0.2 M total ions. 3. **Understanding Urea**: - Urea does not dissociate into ions when dissolved in water; it remains as whole molecules. - Thus, a 0.1 M solution of urea has an effective concentration of particles equal to 0.1 M. 4. **Van't Hoff Factor (i)**: - The Van't Hoff factor (i) is a measure of the number of particles into which a solute dissociates in solution. - For NaCl, i = 2 (since it dissociates into 2 ions). - For urea, i = 1 (since it does not dissociate). 5. **Boiling Point Elevation**: - The elevation in boiling point (ΔTb) is directly proportional to the Van't Hoff factor and the molality of the solution: \[ \Delta T_b = i \cdot K_b \cdot m \] - Here, Kb is the ebullioscopic constant of the solvent, and m is the molality of the solution. 6. **Comparing the Two Solutions**: - For NaCl: \[ \Delta T_b = 2 \cdot K_b \cdot 0.1 \] - For urea: \[ \Delta T_b = 1 \cdot K_b \cdot 0.1 \] - Since the value of ΔTb for NaCl is higher than that for urea, the boiling point of the NaCl solution is indeed higher. 7. **Conclusion**: - Both the assertion (A) and the reason (R) are correct. The assertion is true because NaCl produces more particles in solution compared to urea, leading to a higher boiling point. The reason is also correct as it explains that a higher Van't Hoff factor results in a greater elevation in boiling point. ### Final Answer: - Assertion (A) is true: The boiling point of a 0.1 M solution of NaCl is higher than that of a 0.1 M solution of urea. - Reason (R) is true: Greater the value of Van't Hoff factor, greater the elevation in boiling point of solution containing non-volatile solute.
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Knowledge Check

  • The boiling point of a solution of a non- volatile solute is always ______.

    A
    Lower than the boiling point of solvent
    B
    higher than the boiling point of solvent
    C
    equal to the boiling point of solvent
    D
    independent of the boiling point of the solvent
  • Van't Hoff factor for 0.1 M ideal solution is

    A
    0.1
    B
    1
    C
    0.01
    D
    none of these
  • 1.2 of solution of NaCl is isotonic with 7.2 of solution of glucose .Calculate the van't Hoff factor of NaCl solution?

    A
    `2.36`
    B
    `1.50`
    C
    `1.95`
    D
    `1.00`
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