Two equal masses m are attached by a string. One mass lies at radial distance r from the centre of a horizontal turntable which rotates with constant angular velocity `omega=2` rad `s(1)`, while the second hangs from the string inside the tumtable's hollow spindle (see fig.) The coefficient of static friction between the turntable and the mass lying on it is `mu_(s)=0.5`. The maximum and minimum values of radius such that the mass lying on the turntable does not slide are `r_("max")+r_("min")` in meter is

Explanation

T=mg
`m_("max")omega^(2)=T+mumg`
`mr_("min")omega^(2)=T-mumg`
`m(r_("max+r_("min"))omega^(2)=2mg`
`therefore r_("max")+r_("min")=(2g)/(omega^(2))=5m`