Home
Class 12
MATHS
if f:R rarr R is defined bty f(x)={{:(...

if f:R `rarr` R is defined bty
`f(x)={{:(|[x-5]|, "for" x lt 5),([|x-5|],"for" x ge5):}`
Then (fof)`(-7/2)`=
(here [x] is the greatest integer not exceeding x)

A

`(fof ) (-(11)/(2))`

B

`(fof) (-(9)/(2))`

C

`(fof) ( 3)`

D

`(fof) ((9)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • AP EAMCET ( ONLINE QUESTION PAPER 2018 SOLVED)

    TS EAMCET PREVIOUS YEAR PAPERS|Exercise MATHEMATICS|80 Videos
  • AP EAMCET ENGINEERING ENTRANCE EXAM ONLINE QUESTION PAPER 2019 (SOLVED)

    TS EAMCET PREVIOUS YEAR PAPERS|Exercise Mathematics|80 Videos

Similar Questions

Explore conceptually related problems

Let f:R to R defined by f(x)={{:(2x-1,if x lt 3),(5, if x ge 3):} Then show that Lt_(x to 3) f(x)=5

If f:R rarrR is defined by f(x)=2x+|x| then f(2x)+f(-x)-f(x)=

Knowledge Check

  • If f: R to R defined by f(x) ={{:(2x+5, if, x gt 0),(3x-2, if, x le 0):} then f is

    A
    a function
    B
    one one
    C
    onto function only
    D
    one one onto
  • The value of int_(1)^(a)[x] f' (x) dx, a gt 1 , where [x] denotes the greatest integer not exceeding x is

    A
    `af(a)-{f(1)+f(2)+....+ f([a])}`
    B
    `[a]f(a)-{f(1)+f(2)+....+f([a])}`
    C
    `[a]f([a])-{f(1)+f(2)+....+f(a)}`
    D
    `af([a])-{f(1)+f(2)+....+f(a)}`
  • If f: R rarr R and g:R rarr R are defined by f(x)=x - [x] and g(x)=[x] for x in R , where [x] is the greatest integer not exceeding x , then for every x in R, f(g(x))=

    A
    x
    B
    0
    C
    `f(x)`
    D
    `g(x)`
  • Similar Questions

    Explore conceptually related problems

    Let f: R to R be defined by f(x) = {:{(2x-1 if x lt 3),(5 if x ge 3):} show that Lt_(x to -3)f(x) = 5 .

    If f: R to R is defined by f(x)==[x-3]+|x-4| for x in R then Lt_(x to3-)f(x)=

    If f:R rarr R is defined by f(x)=[2x]-2[x] for x in R , then the range of f is (Here [x] denotes the greatest integer not exceding x)

    If f(x)={:(,(sin (1+[x]))/(x),"for "[x] ne 0),(,0,"for [x]=0"):} where [x] denotes the greatest integer not exceeding x then underset(x to 0-)"Lt" f(x)=

    If f: R to R is defined by f(x) = 2x+|x| , then f(3x) -f(-x)-4x=