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H distance energy of an electron of m...

H distance energy of an electron of mass `5.0 xx 10^(10)` kg is `2.0 xx 10^(-25)` j the wavelength of the electon in nm is approximately

A

1204.3

B

1203.03

C

1104.3

D

994. 3

Text Solution

Verified by Experts

The correct Answer is:
C
Given
Kinetic energy of an electron `=2.0 xx 10^(-23) J`
Mass of electron ` = 9.0 xx 10^(31) kg`
Wavelength of the electron = ?
`lambda = (h )/( sqrt(2 m (KE)) ` (here hh - `6.6 xx 10^(34)` Js )
`lambda = (6.63 xx 10^(-34) Js)/(sqrt(2xx 9.0 xx 10^(-31) kg xx 2xx 10^(-25)j )) `
`lambda = 1.1043 xx 10^(-6) m = (11.043 xx 10^(6))/(10^(9)) nm`
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Knowledge Check

  • Mass of electron = 9.1 xx 10^(-3) kg . The kinetic energy of an electron is 4.55 xx 10^(-25)J . What is its wavelength (in nm) ?

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  • In a photoelectric effect experiment, the kinetic energy of an emitted electron is 1.986 xx 10^(-19) J , when a radiation of frequency 1.0 xx 10^15 s^(-1) hits the metal. What is the threshold frequency of the metal (in s^(-1) )?(Planck's constant = 6.62 xx 10^(-34) Js)

    A
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