H distance energy of an electron of mass `5.0 xx 10^(10)` kg is `2.0 xx 10^(-25)` j the wavelength of the electon in nm is approximately

Options

A. 1204.3
B. 1203.03
C. 1104.3
D. 994. 3

Answer

C

Explanation

Given
Kinetic energy of an electron `=2.0 xx 10^(-23) J`
Mass of electron ` = 9.0 xx 10^(31) kg`
Wavelength of the electron = ?
`lambda = (h )/( sqrt(2 m (KE)) ` (here hh - `6.6 xx 10^(34)` Js )
`lambda = (6.63 xx 10^(-34) Js)/(sqrt(2xx 9.0 xx 10^(-31) kg xx 2xx 10^(-25)j )) `
`lambda = 1.1043 xx 10^(-6) m = (11.043 xx 10^(6))/(10^(9)) nm`