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The quantity of CO(2) in 500 mL of soda ...

The quantity of `CO_(2)` in 500 mL of soda water when packed under 3.34 bar `CO_(2)` pressure at 298 K in g is

A

2.442

B

1.221

C

4.884

D

3.663

Text Solution

Verified by Experts

The correct Answer is:
A
Given, Quantity of `CO_(2)` = 500mL
Pressure of `CO_(2)` = 3.34 bar
Temperature = 298 K in
Henry.s law
`p=K_(H)X xx(x)`
`X=p/K_(H)=3.34` bar = 334000 Pa
= `(3.34xx10^(1))/(1.67xx10^(8))=2.442` Pa
But, we have 500 mL of soda water so that
Volume of water = 500mL
Density of water = 1g/mL
Formula mass = volume `xx` density we get
500 mL of water = 500 g of water
Molar mass of water = `18g//mol^(-1)`
`500/18=27.8" mole "mu` of water
`x=(n_(CO_(2)))/(n_(CO_(2))+n_(H_(2)O))`
Value of moles fraction is very small so it is negligible as compared to 1 we get,
`x=n_(CO_(2))/(n_(H_(2)O))=2xx10^(-7)`
Molar mass of `CO_(2)` is after calculation = 2.442 g
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