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A monochromatic ray of light in incident...

A monochromatic ray of light in incident normally on a refracting face of a prism of angle `30^(@)` . The refractive index of the material of the prism 1.5 .
The angle of emergence will be

A

`32.5^(@)`

B

`20.6^(@)`

C

`48.6^(@)`

D

`18.6^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
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A monochromatic ray of light is incident normally on a refracting face of a prism of angle 30^(@) . If the refractive index of the material of the prism is 1.5 , calculate the angle of emergence and the angle of deviation. [sin48.6^(@) = 0.75]

A ray of light is incident normally on a face of the prism of refracting angle 30^(@) and refractive index sqrt(2) . Calculate the angle of deviation in degree.

Knowledge Check

  • The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A // 2) . The angle of minimum deviation is

    A
    `180^(@) - 3A`
    B
    `180^(@) - 2A`
    C
    `90^(@) - A`
    D
    `180^(@) + 2A`
  • A ray of light is incident normally on one face of a right angled isosceles prism. It then grazes the hypotenuse. The refractive index of the material of the prism is

    A
    1.33
    B
    1.414
    C
    1.5
    D
    1.732
  • Refractive index of the material of an equilateral prism is sqrt(2) .

    A
    For a ray of light, minimum angle of deviation is `30^(@)`
    B
    For a ray of light, minimum angle of deviation is `45^(@)`
    C
    At `45^(@)` angle of incidence, deviation of a ray becomes minimum
    D
    At `60^(@)` angle of incidence, deviation of a ray becomes minimum
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