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Angle between the vectors vecA and vecB ...

Angle between the vectors `vecA and vecB` is `theta`. By resolving them into mutually perpendicular components show that the magnitude of the resultant vector is `(A^2+B^2+2AB cos theta )^(1//2)`.

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Knowledge Check

  • If veca and vecb are mutually perpendicular unit vectors, then the value of (3veca-4vecb)*(2veca+5vecb) is -

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