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A block of mass M rests on an inclined p...

A block of mass M rests on an inclined plane. If the coefficient of friction between the block and the plane is `mu`, then the block will slide down the plane under its own weight when the angle of inclination is

A

` theta gt "tan"^(-1) (mu)`

B

`theta gt "tan"^(-1) ((1)/(mu))`

C

`theta lt "tan"^(-1) (mu)`

D

`thetalt "tan"^(-1) ((1)/(mu))`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A block A of mass m_(1) rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m_(2) is suspended. The coefficient of kinetic friction between the block and the table is mu_(k) . When the block A is sliding on the table the tension in the string is

    A
    `((m_(2)+mu_(k)m_(1))g)/((m_(1)+m_(2)))`
    B
    `((m_(2)-mu_(k)m_(1))g)/((m_(1)+m_(2)))`
    C
    `(m_(1)m_(2)(1+mu_(k))g)/((m_(1)+m_(2)))`
    D
    `(m_(1)m_(2)(1-mu_(k))g)/((m_(1)+m_(2)))`

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