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Two particles, initially at rest due to ...

Two particles, initially at rest due to their mutual attraction move towards each other. When their relative velocity becomes v , velocity of the centre of mass of the system becomes

A

zero

B

v

C

1.5 v

D

3 v

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • Two bodies of masses m_1 and m_2 are initially at rest and infinite distance apart. Due to mutual attraction, they approach each other. When they are r distance apart, their relative velocity of approach is

    A
    `[(2G(m_1+m_2))/r]^(1//2)`
    B
    `[sqrt((2G)/r)((m_1+m_2)/(2))]^(1//2)`
    C
    `[r/(2G(m_1*m_2))]^(1//2)`
    D
    `[(2G)/r*(m_1m_2)]^(1//2)`

  • Two particles A and B (both initially at rest ) start moving towards each other under a mutual force of attraction. At the instant when the speed of A is v and the speed of B is 2v, the speed of the centre of mass is

    A
    zero
    B
    v
    C
    `(3v)/(2)`
    D
    `(3v)/(2)`

  • Two particles of mass m_1 and m_2 approach each other due to their mutual gravitational attraction only then

    A
    accelerations of both the particles are equal
    B
    accelerational of the particle of mass `m_1` is proportional to `m_1`
    C
    acceleration of the particle of mass `m_1` is proportional to `m_2`
    D
    acceleration of the particle of mass `m_1` is inversely proportional to `m_1`

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