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Moment of inertia of a circular ring of ...

Moment of inertia of a circular ring of mass m and radius r about the normal axis passing through its centre is

A

`(mr^(2))/(4)`

B

`mr^(2)`

C

`(mr^(2))/(2)`

D

`(3)/(2) mr^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Write down the expression of moment of inertia of a circular disc ( mass = m, radius = r) about the perpendicular axis passing through its centre.

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Knowledge Check

  • The moment of inertia of a circular disc of mass m and radius r about an perpendicular axis passing through its centre is

    A
    `mr^(2)`
    B
    `(mr^(2))/(4)`
    C
    `(mr^(2))/(2)`
    D
    `(5)/(4) mr^(2)`

  • Moment of inertia of a circular wire of mass m and radius r about its diameter is

    A
    `(1)/(2)mr^(2)`
    B
    `(1)/(4) mr^(2)`
    C
    `mr^(2)`
    D
    `2 mr^(2)`

  • Moment of inertia of a hollow cylinder of mass M and radius r about its own axis is

    A
    `(2)/(3) Mr^(2)`
    B
    `(2)/(5) Mr^(2)`
    C
    `Mr^(2)`
    D
    `(1)/(2)Mr^(2)`

    • Similar Questions

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