Home
Class 11
PHYSICS
A copper collar is to fit tightly about ...

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at `20^(@)C`. The inside diameter of the copper collar at that temperature is 5.98 cm.
To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the steel shaft remains at `20^(@)C`? `(alpha_("cooper")=17 times 10^(-6)K^(-1))`

A

`324^(@)C`

B

`21.7^(@)C`

C

`217^(@)C`

D

`32.4^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER - INTEGER TYPE|4 Videos

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE - WBCHSE|3 Videos

  • EXPANSION OF SOLIDS AND LIQUIDS

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER - MULTIPLE CORRECT ANSWERS TYPE|7 Videos

  • EXPANSION OF GASES

    CHHAYA PUBLICATION|Exercise CBSE Scanner|1 Videos

  • FIRST AND SECOND LAW OF THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos

Similar Questions

Explore conceptually related problems

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at 20^(@)C . The inside diameter of the copper collar at that temperature is 5.98 cm. The tensile stress in the copper collar when its temperature returns to 20^(@)C is (Y=11 times 10^(10)N*m^(-2))

A copper collar is to fit tightly about a steel shaft that has a diameter of 6 cm at 20^(@)C . The inside diameter of the copper collar at that temperature is 5.98 cm. If the breaking stress of copper is 230 N*m^(-2) at what temperature will the copper collar break as it cools?

Diameter of a brass disc at 30^(@)C is 10 cm. What will be the increase in area of the disc at 70^(@)C ? alpha for brass =18 times 10^(-6@)C^(-1) .

At 30^(@)C the diameter of a brass disc is 8 cm. What will be the increase in surface area if it is heated to 80^(@)C ? alpha of brass =18 times 10^(-6@)C^(-1) .

An iron sphere is to be passed through a circular brass ring. At 20^(@)C , the diameter of the sphere is 25 cm and the internal diameter of the ring is 24.9 cm. If both the sphere and the ring are heated together, at what temperature will the sphere just pass through the ring? alpha for iron =1.2 times 10^(-5@)C^(-1) and alpha for brass =2times10^(-5@)C^(-1) .

A steel is 1.5 m long at 20^(@)C . What will be the increase in its length if it is heated up to 100^(@)C?" "alpha for steel =11 times 10^(-6@)C^(-1) .

At 30^@C , the hole in a steel plate has diameter of 0.99970 cm. A cylinder of diameter exactly 1cm at 30^@C is to be slide into the hole. To what temperature the plate must be heated? (Given : alpha_(steel)=1.1xx10^-5//^@C )

A mercury thermometer contains 0.4cm^(3) of mercury at 0^(@)C. The diameter of the capillary tube of the thermometer is 0.2 mm. What should be the length of the scale to measure temperatures between 0^(@)C " to " 100^(@)C ? The coefficient of apparent expansion of mercury =1.7 times 10^(-4@)C^(-1).