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An alloy contains 60% copper and 40% nic...

An alloy contains `60%` copper and `40%` nickel. A piece of this alloy of mass 50 g is heated to `50^(@)C` and than dropped into a calorimeter of water equivalent 10 g containing 40 g of water at `20^(@)C`. Calculate the final temperature of the mixture. Specific heat of copper `="0.09 cal.g"^(-1).^(@)C^(-1)`, and of nickel = `"0.11 cal.g"^(-1).^(@)C^(-1)`

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50 g of an alloy containing 80% copper and 20% silver is heated up to t_(1)=80^(@)C and then dropped in a calorimeter of water equivalent W = 10 g containing m = 90 g of water at t_(2)=20^(@)C . What will be the final temerature of the mixture ? Specific heat capacity of copper and silver are s_(c)=0.09" cal.g"^(-1).^(@)C^(-1) and s_(s)="0.15 cal.g"^(-1).^(@)C^(-1) respectively.

50 g of an alloy containing 60% copper and 40% nickel is dropped in 55 g of water at 10^(@)C , kept in a calorimeter of water equivalent 5 g. The final temperature becomes 20^(@)C . What was the initial temperature of the alloy? Specific heats of copper and nickel are "0.095 cal.g"^(-1).^(@)C^(-1) and "0.11 cal.g"^(-1).^(@)C^(-1) respectively.

Knowledge Check

  • "cal.g"^(-1).^(@)C^(-1) is unit of

    A
    specific heat capacity
    B
    thermal capacity
    C
    water equivalent
    D
    latent heat

  • 50 gm ice at 0^@C is dropped into 50 gm of water at 20^@C . The final temperature of the mixture will be

    A
    `-10^@C`
    B
    `-30^@C`
    C
    `0^@C`
    D
    `10^@C`

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