A monatomic gas at a pressure p having a...

A monatomic gas at a pressure p having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16 V. The final pressure of the gas is (take `gamma = 5//3`)

64 p

32 p

`p//64`

`16 p`

Text Solution

Verified by Experts

The correct Answer is:

1st part : `p_(1)V_(1) = p_(2)V_(2)`
`:. pV = p_(2) xx 2V or, p_(2) = p/2`
2nd part: For adiabatic process
`pV^(gamma)` = constant or, `p_(1) V_(1)^(gamma) = p_(2)^(.) V_(2)^(gamma)`
Here, `p_(1) = p/2, V_(1) = 2V, V_(2) = 16 V, gamma = 5/3`
`:. p_(2)^(.) = p_(1)((V_1)/(V_2))^(gamma) = p/2((2V)/(16V))^(5//3) = p/64`.

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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is : (take gamma=5//3 )

64 P

32 P

`P//64`

16 P

A diatomic gas at pressure P, compressed adiabatically to half of its volume, what is the final pressure-

`(2)^(1.4)P`

`P//(2)^(1.4)`

`(2)^(5/3)P`

`P//(2)^(5//3)`

Two gases have the same initial pressure volume and temperature. They expand to the same final volume, one adiabatically and the other isothermally

The final temperature is greater for the isothermal process

The final pressure is greater for the isothermal process

The work done by the gas is greater for the isothermal process

all the above options are incorrect