Home
Class 11
PHYSICS
Statement I: The root mean square speeds...

Statement I: The root mean square speeds of the molecules of different ideal gases at the same temperature are the same.
Statement II: The average translational kinetic energy of molecules of different ideal gas are same at the same temperature.

A

Statement I is true,statement II is true, statement II is a correct explanation for statement I

B

Statement I si true,statement II is true, statement II is not a correct explanation for statement I.

C

Statement I is true, statement II is false

D

Statement I is false, statement II is true,

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER(Multiple correct answer type)|5 Videos

  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER(Comprehension type)|12 Videos

  • KINETIC THEORY OF GASES

    CHHAYA PUBLICATION|Exercise EXERCISE ( Hot Numerical problems)|22 Videos

  • HYDROSTATICS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|1 Videos

  • MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|18 Videos

Similar Questions

Explore conceptually related problems

Will the rms speed of molecules of different gases at the same temperature be the same?

Will the r.m.s. velocity of gas molecules of different gases at the same temperature be the same?

Knowledge Check

  • The root mean square speed of the perfect gas molecules will be doubled if

    A
    pressure is doubled at constant volume
    B
    pressure is made 4 times at constant volume
    C
    volume is made 4 times at constant pressure
    D
    volume is increased by 41.1% at constant pressure

  • The root mean square speed of the molecules of diatomic gas is u. When the temperature is doubled, the molecules dissociates into two atoms. The new rms speed of the atom is :

    A
    `sqrt2u`
    B
    u
    C
    2u
    D
    4u

  • The ratio of average speed of an oxygen molecule to the rms. speed of a nitrogen molecule at the same temperature is :

    A
    `((3pi)/7)^(1//2)`
    B
    `(7/(3pi))^(1//2)`
    C
    `(3/(7pi))^(1//2)`
    D
    `((7pi)/3)^(1//2)`

    • Similar Questions

    Explore conceptually related problems

    Will the r.m.s. velocity of gas molecules of different gases at the same temperature be the same?

    Will the velocity be equal of two different ideal gas at same temperature? Give reason.

    Prove that the average kinetic energy of a molecule of an ideal gas is direcly proportional to the absolute temperature of the gas.

    Calculate the temperature at which the average translational kinetic energy of the molecules of a gas will be 1/3 rd of that at 180^@C ?

    Use kinetic theory of gases to show that the average kinetic energy of a molecule of an ideal gas is directly proportional to the absolute temperature of the gas.

    Home
    Profile