Home
Class 11
PHYSICS
A siren emitting a sound of frequency 80...

A siren emitting a sound of frequency 800 Hz moves away from an observer towards a cliff at a speed of `15 m cdot s^(-1)`. Then the frequency of sound that the observer hears in the echo reflected from the cliff is (take velocity of sound in air = 330 m `cdot s^(-1))`

A

800 Hz

B

838 Hz

C

885 Hz

D

765 Hz

Text Solution

Verified by Experts

The correct Answer is:
B

Apparent frequency of echo
`n.=n(v/(v-v_(s)))=800(330/(330-15))`
`=(800xx330)/315=838` Hz
The option (B) is correct.
Promotional Banner

Topper's Solved these Questions

  • DOPPLER EFFECT IN SOUND

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|2 Videos
  • DOPPLER EFFECT IN SOUND

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE WITH SOLUTIONS (AIPMT)|1 Videos
  • CIRCULAR MOTION

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos
  • ELASTICITY

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|10 Videos

Similar Questions

Explore conceptually related problems

Determine the frequencies of first three overtones produced in a 50 cm long pipe open at both ends . [Velocity of sound in air = 330 m*s^(-1) ]

If the frequency of a sound wave is 250 Hz and wavelenth is 1.32 m, then what is the velocity of the wave

Find out the frequency of the first overtone emitted by a 1 . 25 m long organ pipe closed at one end. Given , velocity of sound in air = 320 m * s^(-1)

To hear the echo of a sound, the minimum distance between, listener and the reflector should be speed of sound in air =340 m/s)

Find out the frequencies of the fundamental and its nearest harmonic emitted by a 1 m long closed organ pipe. Given, velocity of sound in air 332 m * s^(-1) .

The minimum distance between the source and the reflector, so that an echo is heard is approximately equal to (velocity of sound in air 332 m/s)

Find out the fundamental frequency of a 125 cm long organ pipe closed at one end . Given, velocity of sound in air = 350 m*s^(-1) .