Calculate the molar conductance of 0.01M aqueous KCl solution at `25^(@)C`. The specific conductance of KCl at `25^(@)C` is `14.114 times 10^(-2)Sm^(-1)`.

Explanation

Molar conductance `wedge_(m)=(kappa times 10^(-3))/Mmol^(-1)m^(3)`
Specific conductance `kappa=14.114 times 10^(-2)Sm^(-1)`
Molar conductance `wedge_(m)=(14.114 times 10^(-2) times 10^(-3))/(0.01)`
`" "=14.114 times 10^(-3)Sm^(2)mol^(-1)`.