A bullet of mass 10 g travelling horizontally with a velocity of 150 m `s^(-1)` strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on he bullet.

Explanation

`t = 0.03 s, m = 10g, v = 150 m//s`
`V = u + at`
`a = (-150)/(0.03) = -5000 m//s^(2)`
`V^(2) = u^(2) + 2as`
`S = (150 xx 150)/(10000)`
`S = 2*25` m
`F = ma`
` = (10)/(1000) xx - 5000 = - 500`