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Calculate the number of aluminium ions p...

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide . (Hint : The mass of an ion is the same as that of an atom of the same element , Atomic mass of Al = 27 u)

Text Solution

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`Al_(2)O_(3) = 102 g`
`(12 * 044 xx 10^(23))/(102) xx 0*081`
`= 6 *022 xx 10^(30)` ions
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Calculate the number of aluminium ions present in 0.051 g of aluminium oxide. (Hint : The mass of an ion is the same as Atomic mass of Al 27u).

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Knowledge Check

  • The number of atoms present in 1 g of hydrogen gas is the same as are present in

    A
    0.4 g of He
    B
    22 g of `CO_2`
    C
    6 g of `H_2O`
    D
    12 g of C

  • The number of atoms in 0.004 g of magnesium is close to (atomic mass of Mg = 24)

    A
    24
    B
    `2 xx 10^20`
    C
    `10^20`
    D
    `6.02 xx 10^23`

  • 13.5 g of aluminium when changes to Al^(3+) ion in solution, will lose

    A
    `18.0xx10^(23)` electrons
    B
    `6.022xx10^(23)` electrons
    C
    `3.01xx10^(23)` electrons
    D
    `9.1xx10^(23)` electrons.

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