In thermodynamics, the `P-V` work done is given by
`w=-intdVP_("ext.")`
For a system undergoing a particular process, the work done is ,
`w=-intdV((RT)/(V-b)-(a)/(V^(2)))`
The equation is applicable to a

Options

A. system that satisfies the van der Waals equation of state.
B. process that is reversible and isothermal
C. process that is reversible and adiabatic.
D. process that is irreversible and at constant pressure.

Answer

A, B, C

Explanation

`W=-intP_("ext")dv`
From van der waal equation of state for one mole gas
`(p+(a)/(v^(2)))(v-b)=RT`
`p=((RT)/((v-b))-(a)/(v^(2)))`
For reversible process
`p_("ext")=p_("gas")`
`W=-int((RT)/((v-b))-(a)/(v^(2)))dv`
process is only not applicable for irreversible process.