Home
Class 11
PHYSICS
The acceleration of block is( g=10 ms-2)...

The acceleration of block is( g=10 ms-2)

Answer

Step by step text solution for The acceleration of block is( g=10 ms-2) by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

A small block of wood of relative density 0.5 is submerged in water at a depth of 5 m When the block is released it starts moving upwards, the acceleration of the block is (g=10ms^(-2) )

A block of mass "2kg" is placed on the floor.If "a],[" force of "2.8N" is applied on the block parallel at angle of "30" degree from horizontal,then acceleration of block is (take "g=10m/s^(2)" )

Knowledge Check

  • A small block of wood of relative density 0.5 is submerged in water. When the block is released, it stats moving upwards, the acceleration of the block is (g=10 ms^(-2))

    A
    `5 ms^(-2)`
    B
    `10 ms^(-2)`
    C
    `7.5 ms^(-2)`
    D
    `15 ms^(-2)`
  • In a given figure the acceleration of M is (g=10ms^(-2))

    A
    `20/3ms^(-2)`
    B
    `17 ms^(-2)`
    C
    `(80)/(3)ms^(-2)`
    D
    None of these
  • A 100 N force acts horizontally on a block of 10 kg placed on a horizontal rough surface of coefficient of friction mu=0.5 . If the acceleration due to gravity (g) is taken as 10ms^(-2) , the acceleration of the block (in ms^(-2) ) is

    A
    2.5
    B
    10
    C
    5
    D
    7.5
  • Similar Questions

    Explore conceptually related problems

    A horizontal force of 4 N is applied to a block of mass 2 kg resting on a frictionless table. What is the acceleration of the block in ms^(-2) ?

    In the system shown in the figure blocks A and B have mass m_(1)=2 kg and m_(2)=26//7 kg respectiely. Pulley having moment of inertia I=0.11kgm^(-2) can rotate without friction about a fixed axis. Inner and outer radii of pulley are a=10 cm and b=15 cm respectively. B is hanging with the thread wrapped around the pulley, while A lies on a rough inclined plane. Coefficient of friction being mu=sqrt(3)//10 Calculate as. Tension in each thread, and b. Acceleration of each block (g=10 ms^(-2))

    Figure shown two blocks in contact sliding down an inclined surface of inclination 30^(@) . The block of mass 2 kg and the incline is mu_(1) = 0.20 and the incline is mu_(2) = 0.30 .Find the acceleration of 2.0 kg block g = 10 ms^(-2)

    In the diagram shown in figure. Match the following columns. {:("Colmun I","Column II"),("(A) Absolute acceleration of 1 kg block",(p) 11 ms^(-2)),("(B) Absolute acceleration of 2 kg block",(q)6 ms^(-2)),("(C) Relative acceleration between the two",(r) 17 ms^(-2)),(,(s) "None"):}

    In figure shown if m_(A) = 20 kg and m_(B) = 80 kg. The acceleration of block A if the system is set free to move is beta m//s^(2) . Find the value of beta . (Take g = 10 ms^(-2) )