The acceleration of block is( g=10 ms-2)

A small block of wood of relative density 0.5 is submerged in water. When the block is released, it stats moving upwards, the acceleration of the block is (g=10 ms^(-2))

A small block of wood of relative density 0.5 is submerged in water at a depth of 5 m When the block is released it starts moving upwards, the acceleration of the block is (g=10ms^(-2) )

A block of mass "2kg" is placed on the floor.If "a],[" force of "2.8N" is applied on the block parallel at angle of "30" degree from horizontal,then acceleration of block is (take "g=10m/s^(2)" )

In a given figure the acceleration of M is (g=10ms^(-2))

A 100 N force acts horizontally on a block of 10 kg placed on a horizontal rough surface of coefficient of friction mu=0.5 . If the acceleration due to gravity (g) is taken as 10ms^(-2) , the acceleration of the block (in ms^(-2) ) is

A horizontal force of 4 N is applied to a block of mass 2 kg resting on a frictionless table. What is the acceleration of the block in ms^(-2) ?

In the system shown in the figure blocks A and B have mass m_(1)=2 kg and m_(2)=26//7 kg respectiely. Pulley having moment of inertia I=0.11kgm^(-2) can rotate without friction about a fixed axis. Inner and outer radii of pulley are a=10 cm and b=15 cm respectively. B is hanging with the thread wrapped around the pulley, while A lies on a rough inclined plane. Coefficient of friction being mu=sqrt(3)//10 Calculate as. Tension in each thread, and b. Acceleration of each block (g=10 ms^(-2))

Figure shown two blocks in contact sliding down an inclined surface of inclination 30^(@) . The block of mass 2 kg and the incline is mu_(1) = 0.20 and the incline is mu_(2) = 0.30 .Find the acceleration of 2.0 kg block g = 10 ms^(-2)

In figure shown if m_(A) = 20 kg and m_(B) = 80 kg. The acceleration of block A if the system is set free to move is beta m//s^(2) . Find the value of beta . (Take g = 10 ms^(-2) )