If P is a 3-digit number and Q is the number formed by reversing the digits of P, then find the difference between the place value of the digits in the tenth place.

Options

A. 1
B. 9
C. 0
D. Cannot say

Explanation

To solve the problem, we need to find the difference between the place values of the digits in the tenth place of a three-digit number \( P \) and its reverse \( Q \).

### Step-by-step Solution:

1. **Define the 3-digit number \( P \)**:
Let \( P \) be represented as \( XYZ \), where \( X \), \( Y \), and \( Z \) are the digits of the number. Here, \( X \) is the hundreds place, \( Y \) is the tens place, and \( Z \) is the units place.

2. **Identify the reverse of \( P \)**:
The number \( Q \), formed by reversing the digits of \( P \), will be \( ZYX \). In this case, \( Z \) is now in the hundreds place, \( Y \) is still in the tens place, and \( X \) is in the units place.

3. **Determine the place value of the tens digit in \( P \)**:
The place value of the digit in the tens place of \( P \) (which is \( Y \)) is calculated as:
\[ \text{Place value of } Y = 10 \times Y \]

4. **Determine the place value of the tens digit in \( Q \)**:
The place value of the digit in the tens place of \( Q \) (which is also \( Y \)) is:
\[ \text{Place value of } Y \text{ in } Q = 10 \times Y \]

5. **Calculate the difference between the place values**:
Now, we find the difference between the place values of the tens digit in \( P \) and \( Q \):
\[ \text{Difference} = (10 \times Y) - (10 \times Y) = 0 \]

6. **Conclusion**:
The difference between the place values of the digits in the tens place of \( P \) and \( Q \) is \( 0 \).

### Final Answer:
The difference is \( 0 \).

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